Question

Find the zeros of quadratic polynomial f(x)=abx^2+(b^2-ac)x-bc, and verify the relationship between the zeros and its coefficients

Answer 1

Answer:

Step-by-step explanation:

abx^2 + b^2x - acx - bc

bx(ax + b) - c(ax + b)

(ax + b)(bx - c)

so,

x = -b/a , c/b

so,

SUM OF ZEROES

-b/a+c/b = -(b^2 - ac)/ab

(-b^2 + ac)/ab = (-b^2+ac)/ab

PRODUCT OF ZEROES

(-b/a)(c/b) = -bc/ab

-bc/ab = -bc/ab

hence proved

hope you will understand and please marks as the brainliest :)

Answer 2

Answer:

Hello my friend here is the ans.

Step-by-step explanation is in the attachment.

I hope that this will help u !!!