Question

Find the zeros of
$(1) \: 6x {}^{2} - 7x - 3$
$(2) \: 4x {}^{2} - 4x + 1$
​

Answer 1

$\huge{\red{\underline{\underline{\bold{Solution:-}}}}}$

$→\;{\sf{6x²-7x-3}}$

$→\;{\sf{6x²+2x-9x-3}}$

$→\;{\sf{2x(3x+1)-3(3x+1)}}$

$→\;{\sf{(2x-3)(3x+1)}}$

$➝\;\Large{\bold{x = \frac{3}{2}\;(or)\;\frac{-1}{3}}}$

___________________________

$→\;{\sf{4x²-4x+1}}$

$→\;{\sf{4x²-2x-2x+1}}$

$→\;{\sf{2x(2x-1)-1(2x-1)}}$

$→\;{\sf{(2x-1)(2x-1)}}$

$➝\;\Large{\sf{x = \frac{1}{2}}}$

• ☞ Here the roots are Real and Equal.

$\Large{✓}$

Hope It Helps You ✌️