Question

find the zeros of the following quadractic polynomials and verify the relationship between the zeros and tge coefficients (i)x2-2x-8 ​

Answer 1

Step-by-step explanation:

Step-by-step explanation:x²-2x-8

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2,

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)(x-4)(x+2)

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)(x-4)(x+2)x=4, x= -2

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)(x-4)(x+2)x=4, x= -2Verification

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)(x-4)(x+2)x=4, x= -2VerificationSum of the Zeroes[SOZ]= 4+(-2)

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)(x-4)(x+2)x=4, x= -2VerificationSum of the Zeroes[SOZ]= 4+(-2) = 2

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)(x-4)(x+2)x=4, x= -2VerificationSum of the Zeroes[SOZ]= 4+(-2) = 2Product of the Zeroes[POZ]= 4(-2)

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)(x-4)(x+2)x=4, x= -2VerificationSum of the Zeroes[SOZ]= 4+(-2) = 2Product of the Zeroes[POZ]= 4(-2) = -8

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)(x-4)(x+2)x=4, x= -2VerificationSum of the Zeroes[SOZ]= 4+(-2) = 2Product of the Zeroes[POZ]= 4(-2) = -8-b/a = -(-2)/1

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)(x-4)(x+2)x=4, x= -2VerificationSum of the Zeroes[SOZ]= 4+(-2) = 2Product of the Zeroes[POZ]= 4(-2) = -8-b/a = -(-2)/1 = 2 = SOZ

Step-by-step explanation:x²-2x-8 1.When we add, we have to get -2, 2. when we multiply we have to get -8...The two factors that satisfy the above two conditions are -4 &2x²+2x-4x-8x(x+2)-4(x+2)(x-4)(x+2)x=4, x= -2VerificationSum of the Zeroes[SOZ]= 4+(-2) = 2Product of the Zeroes[POZ]= 4(-2) = -8-b/a = -(-2)/1 = 2 = SOZ c/a = -8/1 = -8 = POZ.