Question

find the zeros of the following quadratic polynomial and verify the relationship between zero and the coefficient

1.x^2-2x-8

Answer 1

that's the answer hope it helps you

Answer 2

Hy
Here is your answer
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${x}^{2} - 2x - 8 \\ {x}^{2} - 4x + 2x - 8 = 0 \\ (x - 4) \: 2 \: (x - 4) = 0 \\( x - 4) \: (x + 2) \: = 0 \\ x - 4 = 0 \: x + 2 = 0 \\ x = - 4 \: x = 2 \\ \alpha = 4 \\ \beta = - 2 \\ ax ^{2} + bx + c = 0 \\ a = 1 \\ b = - 2\\ c = - 8 \\ sum \: of \: root \: = ( \alpha + \beta ) = \frac{ - b}{a} \\ 4 - 2 = 2 \\ 2 = 2 \\ product \: of \: root \: = (\alpha \: \beta ) = \frac{c}{a} \\ 4( - 2) = \frac{ - 8}{1} \\ - 8 = - 8 \\ i \: hope \: you \: understand$
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