find the largest number which divides 438 and 606, leaving remainder 6 in each case
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438-6= 432 = (2)4×(3)3
606-6= 600 = (2)4×(5)2×3
= largest no= HCF of these no.
= (2)4×3= 48.
606-6= 600 = (2)4×(5)2×3
= largest no= HCF of these no.
= (2)4×3= 48.
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