Math, asked by Sneha8590, 6 hours ago

Find the zeros of the following quadratic polynomial and verify the relationship between the zeros and the coefficient

x²-2x-8​

Answers

Answered by Aashutoshanand
1

Step-by-step explanation:

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Answered by akanksha170308
0

Answer:

2 (1) x² - 2x - 8 =x² - 4x + 2x − 8

= x(x − 4) + 2(x − 4)

(x + 2)(x − 4)

So, zeroes are -2 and 4 Now, Verification:

Sum of the zeroes = 2

−b/a = − (-2)/1 = 2

Product of the zeroes = -8

=c/a= -8/1 = -8

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