Find the zeros of the following quadratic polynomial and verify the relationship between the zeros and the coefficient
x²-2x-8
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Answer:
2 (1) x² - 2x - 8 =x² - 4x + 2x − 8
= x(x − 4) + 2(x − 4)
(x + 2)(x − 4)
So, zeroes are -2 and 4 Now, Verification:
Sum of the zeroes = 2
−b/a = − (-2)/1 = 2
Product of the zeroes = -8
=c/a= -8/1 = -8
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