Question

In a Boolean Algebra prove that : a·b+[(a+b')·b] = 1 V a,b € B​

Answer 1

Answer:

I didn't understand this question

Answer 2

Answer:

Step-by-step explanation:a.b+[(a+b').b]'=1

=a.b+[(a+b').b]'

=a.b+[(ab+b'b]'

              (bb'=0)

=a.b+[a.b]'

=(a.b)+1/a.b

=(a.b)(a.b)+1/a.b

=a.a)(b.b)+1/a.b

         (a.a=a)

=1