Question

find the zeros of the following quadratic polynomial and verify the relationship between the zeros and the coefficient 6 x square - 3 - 7x​

Answer 1

Answer:

Step-by-step explanation:

=6x²-7x-3

=6x²+2x-9x-3

=2x(3x+1)-3(3x+1)

=(2x-3)(3x+1)

⇒2x-3=0                                    or                            ⇒3x+1=0

⇒x=3/2                                       or                           ⇒ x= - 1/3

α=3/2 ,β= - 1/3

⇒α+β= -b/a

⇒3/2+(-1/3)= - (-3)/6

⇒3/2-1/3=1/2

⇒7/6 =1/2

⇒αβ=c/a

⇒ 3/2(-1/3)= -7/6

⇒-1/2= -7/6

⇒1/2=7/6      

Answer 2

Answer: Hope its helpful

Step-by-step explanation: a=6 , b = -9 , c = -3

6x^2 -7x-3 = 0

6x^2 -9x +2x -3 = 0

3x(2x-3) + 1(2x-3) = 0

3x+1 = 0 and 2x-3 = 0

X= -1/3 X= 3/2

I'm taking a and b for alpha and beta

a+b =-b/a

-1/3+3/2 = -(-7)/6

-2+9/6 = 7/6

7/6 = 7/6

ab = c/a

-1/3×3/2= -3/6

-3/6 = -3/6

Hence, verified.