Find the zeros of the following quadratic polynomial and verify the relationship between the zeros and the coefficients?
#4u2+8u! Plz solve fast: exam tension
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let p(x)=4u^2+8u
=4u(u+2)
Here,p(x)=0
thus, 4u(u+2)=0
or, 4u=0 or, u+2=0
or, u=0 or, u = -2
Hence , zeroes of p(x) are 0 and (-2)
relationship
sum= 0+(-2)
=-2
=-2/1
=-8/4
= -b/a
&, product=0*(-2)
=0
=c/a
henitozhimo234:
Thnx alot
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