Question

find the zeros of the following
quadratic polynomials and verify
the relationship between the zeroes. and the coefficients. (i)
${x }^ {2} - 2x - 8$
​

Answer 1

Step-by-step explanation:

x^2 -2x -8

x^2 - 4x +2x -8

x(x-4) 2(x-4)

(x+2) (x-4)

x = -2

x = 4

Answer 2

Answer:

Step-by-step explanation:

(i)    2

x  2x 8  x  4 x  2

The value of 2

x 2x  8 zis ero when x − 4 = 0 or x + 2 = 0, i.e., when x  

= 4 or x = −2

Therefore, the zeroes of 2

x 2x  8are 4 and −2.

Sum of zeroes = 2 

2

Coefficient of x

4 2

1 Coefficient of x



  2  

Product of zeroes    

2

8 Constant term 4x 2

1 Coefficient of x

  8  