Question

of a building consists of 3000 tiles which are rhombus shaped. The diagonals of
cach of the tiles are 45 cm and 30 cm. Find the total cost of polishing the floor, if cost per
mis 2.50.​

Answer 1

Answer:

Area of one tiles=1/2×d1÷d2

=1/2×45×30

=675 cm square.

Area of 3000 tiles=3000×675

=2025000 cm square

=20250 m square.

Cost of polishing = 20250×2.50

=Rs 50625.

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Answer 2

d1= 45cm , d2= 30cm

Number of tiles= 3000

Rate per m²= ₹2.50

Area of Rhombus= 1/2×d1×d2

= (1/2) × 45 × 30=675

Area of 1 tile= 675 cm² = 675/10000 m²

Area of 3000 tiles= 3000 × (675/10000)

[1cm²= 1/10000m²]

cost of Polishing the floor

= Total Area × rate

= (3000 × 675 ×2.50)

=50625

Hence the total cost of polishing the floor = rupees 50625

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