Question

find the zeros of the following quadratic polynomials and verify the relationship between the zeros and the coefficient 4u^+8u

Answer 1

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

q(u) = 4u² + 8u

= 4u(u + 2)

q(u) = 0

u = 0

u = -2

Zeroes are 0 and -2

We have

a = 4 , b = 8 and c = 0

Sum of zeroes = α + β

= 0 + (-2)

= -2

${\rightarrow -\dfrac{b}{a}=\dfrac{8}{4}=-2}$

${\rightarrow\alpha + \beta=-\dfrac{b}{a}}$

Product of zeroes = α × β

= 0 × (-2)

= 0

${\rightarrow\dfrac{c}{a}=\dfrac{0}{4}=0}$

${\rightarrow\alpha\times \beta=\dfrac{c}{a}}$

$\bold{\boxed{Hence\;verified}}$