Question

find the zeros of the function f(x)=(x+3)(8x-4)+(x+3)(x+3).

Answer 1

x(8x-4)+3(8x-4)+(x-3)(x-3)

8x^2-4x+24x-12+x^2+3x+3x+9

8x^2+20x-12+x^2+6x+9

Answer 2

Answer:

Step-by-step explanation:

f(x) = (x + 3)(8x - 4 + x + 3)

f(x) = (x + 3)(9x - 1)

x + 3 = 0 ⇒ $x_{1}$ = - 3

9x - 1 = 0 ⇒ $x_{2}$ = $\frac{1}{9}$