Question

find the zeros of the given polynomial root 3 x2 - 8 x + 4 root by 3

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

$\sqrt{3} {x}^{2} - 8x + 4 \sqrt{3} = 0$

$\sqrt{3} {x}^{2} + 6x + 2x + 4 \sqrt{3} = 0$

$\sqrt{3} x(x + 2 \sqrt{3} ) + 2 (x + 2 \sqrt{3} ) = 0$

$( \sqrt{3} x + 2)(x + 2 \sqrt{3} ) = 0$

$x \: = - 2 \div \sqrt{3}$

$and$

$x = - 2 \sqrt{3}$

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