find the zeros of the polynomial 2x(square) - 2x -8 . also verify the relationship between zero and coefficient of polynomial
Answers
Answered by
1
2x² - 2x - 8 =0
dividing by 2
x² - x - 4 = 0
x = -1 + √1-(-4)
first root,
= -1 + √5/2
other root,
= -1 -√5/2
dividing by 2
x² - x - 4 = 0
x = -1 + √1-(-4)
first root,
= -1 + √5/2
other root,
= -1 -√5/2
Similar questions