find the zeros of the polynomial 2x square +7x-4
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2x² + 7x - 4
2x² + 8x - x - 4
2x(x + 4) - 1(x + 4)
(2x - 1) (x + 4)
now
2x - 1 = 0
x = 1/2
or
x + 4 = 0
x = -4
2x² + 8x - x - 4
2x(x + 4) - 1(x + 4)
(2x - 1) (x + 4)
now
2x - 1 = 0
x = 1/2
or
x + 4 = 0
x = -4
pradeepkiccha:
tanxx
Answered by
1
Answer:
2x² + 7x - 4
2x² + 8x - x - 4
2x(x + 4) - 1(x + 4)
(2x - 1) (x + 4)
now
2x - 1 = 0
x = 1/2
or
x + 4 = 0
x = -4
Step-by-step explanation:
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