Question

Find the zeros of the polynomial 3x ^ 2 + 5x + 13​

Answer 1

Step-by-step explanation:

Instead of alpha and beta let us take m and n.

Comparing the equation 3x^2–5x-2 with ax^2+bx+c we get a=3,b=-5 and c=-2.

m and n are the zeroes of the above polynomial.

So. m+n = -b/a => m+n = 5/3

mn = c/a => mn = -2/3

Now m^2 + n^2 = (m+n)^2 - 2mn

= (5/3)^2 - 2(-2/3) = 25/9 + 4/3

= (25+12)/9 = 37/9.