Question

Find the zeros of the polynomial√3x^2-8x+4√3

Answer 1

Answer:

Step-by-step explanation:

√3x^2-8x+4√3=0

√3x^2-6x-2x+4√3=0

√3x(x-2√3)-2(x-2√3)=0

(√3x-2)(x-2√3)=0

√3x-2=0. or. x-2√3=0

X=2/√3. or X=2√3