THE THIMBLE OF A SCREW GAUGE HAS 50 DIVISIONS. THE SCREW ADVENCES 3MM WHEN IT IS TURNED THROUGH 6 ROTATIONS FIND ITS PITCH AND LEAST COUNT
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Answered by
0
Answer:
Pitch=3/6=0.5 cm.
Least count=(smallest main scale reading) /no of division on thimble
L. C=1mm/50=0.02mm
Answered by
1
Answer:pitch =0.5mm
L.C=0.01mm
Explanation:
Pitch of the screw=distance travelleed by the screw/no of rotations
=3/6
=0.5mm
L.C=PITCH OF THE SCREW/NO OF HEAD SCALE DIVISIONS
=0.5/50
=0.01mm
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