Question

Find the zeros of the polynomial 4√3 y 2 + 5 y - 2√3 and verify the relationship between the zeros and its coefficients

Answer 1

Answer:

Brainly.in

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Secondary School Math 5 points

Find the zeros of the quadratic polynomial 4 root 3 X square + 5 x minus 2 root 3 and verify the relationship between the zeros and the coefficients.

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Answers

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Panzer786

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Heya !!!

P(X) => 4✓3X²+5X-2✓3

=> 4✓3X² + 8X -3X - 2✓3

=> 4X ( ✓3X + 2) - ✓3( ✓3X + 2)

=> (✓3X +2) ( 4X- ✓3) = 0

=> (✓3X+2) = 0 OR (4X-✓4) = 0

=> X = -2/✓3 OR X = ✓4/4

Let Alpha = -2/✓3 and Beta = ✓4/4

Relationship between zeroes and Coefficient

Sum of zeroes = Alpha + Beta = ( -2/✓3 + ✓4/4) = -8 + 4/4✓3 = -5/ 4✓3 = - (Coefficient of X/Coefficient of X²)

And,

Product of zeroes = Alpha × Beta = -2/✓3 × ✓3/4 = -2✓3/4✓3 = Constant term/Coefficient of X².

HOPE IT WILL HELP YOU....... :-)

Answer 2

Answer:

- $\sqrt{3}$/4  and 2/$\sqrt{3}$ are the zeros of the polynomial equation

Step-by-step explanation:

Given polynomial equation is  4$\sqrt{3$$y^{2}$ - 5y - 2$\sqrt{3$  =  0

zeros of the polynomial  are

   4$\sqrt{3$$y^{2}$ - 5y - 2$\sqrt{3$  =  0

     4$\sqrt{3$$y^{2}$ - 8y + 3y - 2$\sqrt{3$ = 0

     4y( $\sqrt{3}$y - 2)  + $\sqrt{3}$( $\sqrt{3}$y - 2) = 0

   ⇒ (4y + $\sqrt{3}$)( $\sqrt{3}$y - 2) = 0

   ⇒  (4y + $\sqrt{3}$) = 0  or  ( $\sqrt{3}$y - 2) = 0

  ⇒  4y  = - $\sqrt{3}$   or    $\sqrt{3}$y - 2  = 0

  ⇒ y = - $\sqrt{3}$/4    or  y = 2/$\sqrt{3}$

∴ - $\sqrt{3}$/4  and 2/$\sqrt{3}$ are the zeros of the polynomial equation

The project code is #SPJ2.