Question

Find the zeros of the polynomial 4√3x² + 5x - 2√3. And verify the relationship between the zeros and it's coofficients.

Answer 1

4√3 x² + 5x - 2√3

x= -5 ± √25+96
-------------------
8√3
-5± 11
---------
8√3

-5+11. -5-11
------ , ---------
8√3. 8√3

3 / 4√3. , -2 / √3

let roots be alpha, beta

alpha+beta = -b/a
from eq. -5 / 4√3

3 /4√3 + (-2 / √3)
3 - 8 / 4√3. = -5/4√3

alpha x beta from eq. - 1/2
3/4√3 x -2/√3
-6/12 = -1/2

Answer 2

Hi friend ,

4√3 x^2 + 5x -2√3 (splitting the middle term)

=4√3 x^2 +(8-3)x -2√3

=4√3(√3x+2)-√3(√3x+2)

= (√3x+2) (4x-3)

x = -2/√3
x = √3/4

So, alpha + beta = -b/a

= -5/4√3

Sum of zeros = -2/√3 + √3/4
= -5/4√3

Alpha×beta = c/a

= -2√3/4√3

= -1/2

Product of zeros = -2/√3 × √3/4

= -2√3/4√3

= -1/2

Since the products and sum of zeros are same...Hence verified..

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Hope this helped u..
PLZ MARK AS BRAINLIEST..



Hope this helped u..
PLZ MARK AS BRAINLIEST...