Find the zeros of the polynomial 4 x^2- 4 x- 3 and verify the relation between zeroes and its coefficients?
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Hii friend,
=> 4X²-4X-3
=> 4X²-6X+2X-3
=> 2X(2X-3) + 1(2X-3)
=> (2X-3)(2X+1)
=> (2X-3) = 0. OR (2X+1) = 0
=> 2X = 3. OR 2X = -1
=> X = 3/2. OR X = -1/2
Two zeros of the QUADRATIC POLYNOMIAL 4X²-4X-3 is 3/2 and -1/2.
Let Alpha = 3/2 and Beta = -1/2
Sum of the zeros = (Alpha + Beta) = (3/2+ 1/2) = (3+1/2) = 4/2
Product of zeros = (Alpha × Beta) = 3/2 × -1/2 = -3/4 = Constant term/ Coefficient of X².
HOPE IT WILL HELP YOU...... :-)
=> 4X²-4X-3
=> 4X²-6X+2X-3
=> 2X(2X-3) + 1(2X-3)
=> (2X-3)(2X+1)
=> (2X-3) = 0. OR (2X+1) = 0
=> 2X = 3. OR 2X = -1
=> X = 3/2. OR X = -1/2
Two zeros of the QUADRATIC POLYNOMIAL 4X²-4X-3 is 3/2 and -1/2.
Let Alpha = 3/2 and Beta = -1/2
Sum of the zeros = (Alpha + Beta) = (3/2+ 1/2) = (3+1/2) = 4/2
Product of zeros = (Alpha × Beta) = 3/2 × -1/2 = -3/4 = Constant term/ Coefficient of X².
HOPE IT WILL HELP YOU...... :-)
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