Math, asked by sabirhalder124, 9 months ago

find the zeros of the polynomial 49 x square - 64

Answers

Answered by apple123456789

7

49x^2-64=0
49x^2=64
x^2=64/49
x=8/7

Answered by pradnya250604

12

Answer:

49x²-64=0

49x²+0x-64=0

49x²+56x-56x-64=0

7x(7x+8)-8(7x+8)=0

(7x-8)(7x+8)=0

7x-8=0 7x+8=0

x=8/7 x= -8/7

zeroes are -8/7 and 8/7

Step-by-step explanation:

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