Question

FIND THE ZEROS OF THE POLYNOMIAL 5X^2-4X+3​

Answer 1

Answer:

Step-by-step explanation:

we have to find the zeros of polynomial 5x² - 4 - 8x .

so, 5x² - 4 - 8x = 0

or, 5x² - 8x - 4 = 0

or, 5x² - 10x + 2x - 4 = 0

or, 5x(x - 2) + 2(x - 2) = 0

or, (5x + 2)(x - 2) = 0

or, x = 2 and -2/5

verification : sum of zeros = -coefficient of x/coefficient of x²

LHS= sum of zeros = 2 - 2/5 = 8/5

RHS= -coefficient of x/coefficient of x² = -(-8)/5 = 8/5

LHS = RHS

again, product of zeros = constant/coefficient of x²

LHS = product of zeros = 2 × (-2/5) = -4/5

RHS = constant/coefficient of x² = -4/5

LHS = RHS

hence, verified.

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