find the zeros of the polynomial a) p (x)=2x-1 b) p (y)=4y+64
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Answer:
(a) x = 1/2
(b) y = -16
Step-by-step explanation:
(a) p(x) = 2x -1
put p(x) =0
2x - 1 = 0
2x = 1
x = 1/2
Hence the zero of the polynomial is at x = 1/2.
(b) p(y) = 4y + 64
put p(x) = 0
4y + 64 = 0
4y = -64
y = -16
Hence the zero of the polynomial is at y = - 16.
Hope you understand it
Thank you
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