Question

Find the zeros of the polynomial
f(x)= x²+7x+ +12
and verify the relation between ith zeros
and cofficients​

Answer 1

Answer:

zeroes = (-3),(-4)

Step by step explanation:

x^2 + 7x +12=0

x^2+3x+4x+12=0

x(x+3) + 4(x+3)=0

(x+3)=0 (x+4)=0

x=(-3) x=(-4)

Verification:

• Sum of the zeroes =

$\alpha + \beta$

=(-3) + (-4)

= -3-4

= -7

= -b/a

= -7/1

• Product of the zeroes =

$\alpha \times \beta$

= (-3)×(-4)

= 12

= c/a

= 12/1

Hence verified..

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