Question

k
$kx {}^{2} - 2kx + 6 = has \: equal \: roots$
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Answer 1

$k {x}^{2} - 2kx + 6 \: has \: </em></strong><strong><em>equal</em></strong><strong><em> \: roots \\ a = k \: \\ b = - 2k \\ c = 6 \\ so \: \: \: d \: = 0 \\ = > {b}^{2} - 4 ac = 0 \\ = > {( - 2k)}^{2} - 4 \times k \times 6 = 0 \\ = > 4 {k}^{2} - 24k = 0 \\ = > 4k(k - 6) = 0 \\ = > k = 6</em></strong><strong><em> </em></strong><strong><em>\</em></strong><strong><em>:</em></strong><strong><em> </em></strong><strong><em>or</em></strong><strong><em> </em></strong><strong><em>\</em></strong><strong><em>:</em></strong><strong><em> </em></strong><strong><em>0</em></strong><strong><em> </em></strong><strong><em>$

so value of k is 6 or 0

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