find the zeros of the polynomial f(x)x³+4x²-9x-36,if 2 of its zeroes are equal in magnitude but opposite in sign
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Let α, b, and γ be the zeroes of x3 – 3x2 – 25x+ 75
Given:
α = –b
Now
Sum of roots = α + b + γ = α – α + γ = γ =3
and product of roots = αbγ = α(–α)γ
= – α2 γ = – 75
⇒ 3α2 = 75
So, the required zeroes are 3, 5 and – 5
Given:
α = –b
Now
Sum of roots = α + b + γ = α – α + γ = γ =3
and product of roots = αbγ = α(–α)γ
= – α2 γ = – 75
⇒ 3α2 = 75
So, the required zeroes are 3, 5 and – 5
maya51:
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