Math, asked by Rythm14, 1 year ago

Find the zeros of the polynomial for p(x) =x^2 +2x + 1

Answers

Answered by siddhartharao77
5

Given p(x) = x^2 + 2x + 1.

Zero of the polynomial is p(x) = 0.

= > x^2 + 2x + 1 = 0

= > x^2 + x + x + 1 = 0

= > x(x + 1) + 1(x + 1) = 0

= > (x + 1)(x + 1) = 0

= > (x + 1)^2 = 0

= > x = -1.


Therefore, -1 is the zero of the polynomial.


Hope it helps!



Rythm14: Happy ganesh chaturthi
Rythm14: and thanks al lot
siddhartharao77: Thank you..Wish u the same :-)
Answered by Divyaalia
2
Hey mate, here is your answer -:)

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 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {x}^{2} + 2x + 1 = 0 \\ \: \: \: \: \: {x}^{2} + (1 + 1)x + 1 = 0 \\ \: \: \: \: \: \: \: \: \: \: {x}^{2} + x + x + 1 = 0 \\ x(x + 1) + 1( x+ 1) = 0 \\ \: \: \: \: \: \: \: \: \: \: (x + 1)(x + 1) = 0 \\ \\ x + 1 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x + 1 = 0 \\ \: \: \: \: \: \: \: x = - 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = - 1

The zeros of the polynomial are -1 and -1

HOPE it helps to you!!!
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