Find the zeros of the polynomial for p(x) =x^2 +2x + 1
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Answered by
5
Given p(x) = x^2 + 2x + 1.
Zero of the polynomial is p(x) = 0.
= > x^2 + 2x + 1 = 0
= > x^2 + x + x + 1 = 0
= > x(x + 1) + 1(x + 1) = 0
= > (x + 1)(x + 1) = 0
= > (x + 1)^2 = 0
= > x = -1.
Therefore, -1 is the zero of the polynomial.
Hope it helps!
Rythm14:
Happy ganesh chaturthi
Answered by
2
Hey mate, here is your answer -:)
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
The zeros of the polynomial are -1 and -1
HOPE it helps to you!!!
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The zeros of the polynomial are -1 and -1
HOPE it helps to you!!!
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