Question

Find the zeros of the polynomial function f(x)=4x²-25​

Answer 1

Answer:

The zeroes of given polynomial are=7, (-3)

Step-by-step explanation:

Here, As given in question,

f(x)=4x^2-25

So, now, on doing square root of it, we get,

=(2x)^2-(5)^2

=Here, the identity which is applied, is,

=a^2-b^2 which is equal to = (a+b)(a-b)

=(2+5) (2-5)

As we have to find out two zeroes of it,

=(2+5)=0, (2-5)=0

=7, =-3

Hence, two zeroes are 7, (-3).

Thank you

Answer 2

Answer:

The zeroes of given polynomial are=7, (-3)

Step-by-step explanation:

Here, As given in question,

f(x)=4x^2-25

So, now, on doing square root of it, we get,

=(2x)^2-(5)^2

=Here, the identity which is applied, is,

=a^2-b^2 which is equal to = (a+b)(a-b)

=(2+5) (2-5)

As we have to find out two zeroes of it,

=(2+5)=0,

= 7

and

(2-5)=0

= -3

Hence, two zeroes are 7, (-3)