Question

find the zeros of the polynomial P of x = x square - 3​

Answer 1

$p(x) = {x}^{2} - 3 \\ {x}^{2} - 3 = 0 \\ {x}^{2} = 3 \\ x = \sqrt{3} \\ or \: x = - \sqrt{3}$

Answer 2

Answer-

x = x²-3

x²-3-x = 0

x²-x-3 =0

Using quadratic formula we get

1+- √1+12/ 2

= 1+-√13/2

The zeroes are

1+√13/2 and 1-√13/2