Question

Find the zeros of the polynomial p(x) = 4√3x^2 + 5x – 2√3 and verify the relationship between the zeros and its coefficients.

Answer 1

Answer:

you can solve this by following formula

Answer 2

$\alpha +\beta =\frac{-b}{a}=\frac{5}{4\sqrt{3} }\\\alpha \beta =\frac{c}{a}=\frac{2\sqrt{3}}{4\sqrt{3}}$

Step-by-step explanation:

$(4\sqrt{3} x^2+8x)-(3x-2\sqrt{3)}\\4x(\sqrt{3x} +2)-\sqrt{3} (\sqrt{3x} +2)\\(4x-\sqrt{3} )(\sqrt{3x} +2)\\4x-\sqrt{3} =0\\4x=\sqrt{3}\\ x=\frac{\sqrt{3}} {4}\\or\\\sqrt{3x} =-2\\x=\frac{-2}{\sqrt{3} }$

For verify the relationship between zeroes and its coefficients

$\alpha +\beta =\frac{-b}{a}=\frac{5}{4\sqrt{3} }\\\alpha \beta =\frac{c}{a}=\frac{2\sqrt{3}}{4\sqrt{3}}$