Find the zeros of the polynomial:p(x)=(x-2)²- (x+2)²
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Hey dear here is your answer!!!!
To find the zeroes ....
We can use the following identity..
(a^2 - b^2)=(a+b)(a-b)...
Put these values...
=>(x-2)^2-(x+2)^2=( x-2+x+2)(x-2-x-2)
=>2x(-4)
=>-8x
Zeroes is -1/8
Hope it helps u...☺️☺️
To find the zeroes ....
We can use the following identity..
(a^2 - b^2)=(a+b)(a-b)...
Put these values...
=>(x-2)^2-(x+2)^2=( x-2+x+2)(x-2-x-2)
=>2x(-4)
=>-8x
Zeroes is -1/8
Hope it helps u...☺️☺️
Karthik2580:
perfect answer and thankyou very much
thanks dear
ur welcome mam
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