Find the zeros of the polynomial p(x)= x^2-(√3+1)x+√3
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venkat4613:
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x^2-(root3-1)x+ root3=0
x^2- root3x-x+root3=0
x(x-root3)-1(x-root3)=0
(x-root3) (x-1)=0
x=1 or root3
x^2- root3x-x+root3=0
x(x-root3)-1(x-root3)=0
(x-root3) (x-1)=0
x=1 or root3
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