Question

Find the zeros of the polynomial p(x)=(x-2) (x+2) (x+3)

Answer 1

$p(x) = (x - 2)(x + 2)(x + 3) \\ \\ (x - 2) = 0 \\ x = 2 \\ \\ (x + 2) = 0 \\ x = - 2 \\ \\ (x + 3) = 0 \\ x = - 3$

hence zeros are 2, -2, -3

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