find the zeros of the polynomial p(x) = x(x-2)(x+3)
Answers
Answered by
24
HOLA
==============
P( x ) = 0
p ( x ) = x ( x - 2 ) ( x + 3 )
➡ p ( x ) = ( x - 2 ) + ( x + 3 )
x = -2 ... x = 3
==========≠========
HOPE U UNDERSTAND ☺☺
==============
P( x ) = 0
p ( x ) = x ( x - 2 ) ( x + 3 )
➡ p ( x ) = ( x - 2 ) + ( x + 3 )
x = -2 ... x = 3
==========≠========
HOPE U UNDERSTAND ☺☺
shivamkhanchanpaoqh1:
bro but in my assignment ans is given (0,2,-3)
Answered by
31
Hi friends
Here is ur answer
p(x)=x(x-2)(x+3)
x=0
x-2=0
x=2
x+3=0
x= -3
The zeroes of the given polynomial are 0, 2, -3
Hope it helps
Pls plssss mark it as brainliest
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