Question

Find the zeros of the polynomial p (x)=x2-3x-28 and verify the relationship between zeros and coefficients of the polynomial.

Answer 1

Step-by-step explanation:

x^2-3x-28

=x^2-7x+4x-28

=x(x-7)+4(x-7)=

=(x-7)(x+4)

=x=7and x=-4

• Let the zeroes of the polynomial be
• $\alpha \: and \: \beta \\ we \: know \: sum \: of \: zeroes \: = \alpha + \beta \\ = 7 + { - 4} \\ = 3 \\ product \: of \: zeroes \: = \alpha \beta \\ 7 \times - 4 = - 28$
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