Question

Find the zeros of the polynomial x^2+1/6x-2 and verify the relationship between its zeros and coefficients of the polynomial​

Answer 1

Step-by-step explanation:

Polynomial : x2+16x−2

Comparing with standard equation, we get

a = 1, b = 16 , c = -2

To find zero, equate it with 0

=>x2+16x−2=0

Multiply by 6

=>6x2+x−12=0

=>6x2+9x−8x−12=0

=> 3x(2x+3) - 4(2x+3) = 0

=> (2x+3)(3x-4) = 0

2x+3 = 0 Or 3x-4 = 0

=> x = −32 or 43

We know

Sum of zeroes = −ba

=> −32+43=−16

=> −9+86=−16

=> −16=−16

Also

Product of zeroes = ca

=> −32×43=−21

=> -2 = -2

Hence verified