Find the zeros of the polynomial x^2+1/6x-2 and verify the relationship between its zeros and coefficients of the polynomial
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Step-by-step explanation:
Polynomial : x2+16x−2
Comparing with standard equation, we get
a = 1, b = 16 , c = -2
To find zero, equate it with 0
=>x2+16x−2=0
Multiply by 6
=>6x2+x−12=0
=>6x2+9x−8x−12=0
=> 3x(2x+3) - 4(2x+3) = 0
=> (2x+3)(3x-4) = 0
2x+3 = 0 Or 3x-4 = 0
=> x = −32 or 43
We know
Sum of zeroes = −ba
=> −32+43=−16
=> −9+86=−16
=> −16=−16
Also
Product of zeroes = ca
=> −32×43=−21
=> -2 = -2
Hence verified
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