Question

Find the zeros of the polynomial x^2-3x-m(m+3)

Answer 1

Heya !!

Here's your answer.. ⬇⬇
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x² - 3x - m( m+3 ) = 0

x² + mx - ( m+3 )x - m( m+3 ) = 0

x( x+m ) - ( m+3 )( x+m ) = 0

{ x - ( m+3 )} ( x + m ) = 0

x = m+3 or..

x = ( -m )
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Hope it helps..
Thanks :)

Answer 2

The zeros of the polynomial x² – 3x - m(m +3) are - m , m + 3

Given :

The polynomial x² – 3x - m(m +3)

To find :

The zeroes of the polynomial

Solution :

Step 1 of 2 :

Write down the given polynomial

The given polynomial is

x² – 3x - m(m +3)

Step 2 of 2 :

Find the zeroes of the polynomial

We find the zeroes of the polynomial as below

For Zeroes of the polynomial we have

$\sf {x}^{2} - 3x - m(m + 3) = 0$

$\sf \implies {x}^{2} - 3x - {m}^{2} - 3m = 0$

$\sf \implies {x}^{2} - {m}^{2} - 3x - 3m = 0$

$\sf \implies (x + m)(x - m) - 3(x + m ) = 0$

$\sf \implies (x + m)(x - m - 3) = 0$

x + m = 0 gives x = - m

x - m - 3 = 0 gives x = m + 3

So the zeroes are - m & m + 3

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