Question

find the zeros of the polynomial x^2+x-p(p+1)

Answer 1

Answer:

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➡ x² + x - p(p + 1)

➡ x² + (p + 1)x - px - p(p + 1) = 0

➡ x(x - p) + (p + 1) (x - p) = 0

➡ (x + p + 1) ; (x - p) = 0

➡ x + (p + 1) = 0 ; x - p = 0

➡ x = 0 - (p + 1) ; x = 0 + p

➡ x = - (p + 1) ; x = p

Therefore, x = - (p + 1) & p

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Step-by-step explanation:

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