Question

if A+B=C and tanA= p tan B then sin(A-B) ? please don't spam it's urgent​

Answer 1

Answer:

sin(C)(1-p)/(1+p)

Step-by-step explanation:

sin(A)/cos(A)=pain(B)/cos(B)

so if we use sin(A-B) =sinA cosB -cosAsinB

=sinAcosB(1-p)

Given A+B=C

so sin (A+B) = sinc

sinAcosB(1+p). =sinC

so finally sinAcosB =sinC/(1+p)

sin(A-B) =sinc(1-p)/(1+p)