find the zeros of the polynomial x3 - 5 x2 - 16 X + 80 if its two zeros are a equal in magnitude but opposite in sign
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f(x) = x³ -5x² -16x +80
let roots be a,b,-a
sum of roots = a-a+b = b = 5/1 = 5
so one of the factors of f(x) is (x-5)
f(x) = (x-5) (x² - 16)
= (x-5)(x-4)(x+4)
zeroes are = 5,4,-4
let roots be a,b,-a
sum of roots = a-a+b = b = 5/1 = 5
so one of the factors of f(x) is (x-5)
f(x) = (x-5) (x² - 16)
= (x-5)(x-4)(x+4)
zeroes are = 5,4,-4
Aryan20030224:
thanks pari
Its alright.
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