Math, asked by aayushgupta299oyhpyt, 1 year ago

Find the zeros of the quadratic polynomial 2x square minus 2 root 2 x minus 3

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Answered by STR9
26
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Answered by digi18
81

2x {}^{2}  - 2 \sqrt{2} x - 3

2x {}^{2}   +  \sqrt{2}x   - 3  \sqrt{2}x  - 3


 \sqrt{2} x( \sqrt{2} x + 1) - 3( \sqrt{2} x + 1)

( \sqrt{2} x - 3)( \sqrt{2} x + 1)


x = 3 \div  \sqrt{2}  \:  \:  \: and \:  - 1 \div  \sqrt{2}



Thanks
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