find the zeros of the quadratic polynomial 3 x square -
2 and verify the relationship between the zeros and the coefficient
Answers
Answered by
7
As in the given question 3x²-2= 2
so,
3x²-2=0
3x²=2
x²=2/3
on removing square from lHS, we put under root in RHS
x=2/3 and -2/3
a=2/3 , b= -2/3
verification.,
on comparing with ax²+bx+c=0
a = 3
b=0
c=-2
sum of zeroes = a+b = -b/a( -coeff. of x)/(coeff. of x²)
=> 2/3-2/3=0/3
=> 0=0
product of zeroes = a.b = c/a ( constant term)/( coeff. of x²)
=> 2/3.-2/3 = -2/3
=> -4/6 = -2/3
=> -2/3 = -2/3
So , the roots are 2/3 & -2/3...
Hope , it helps you....
please hit like button and remark as brainliest answer.....
so,
3x²-2=0
3x²=2
x²=2/3
on removing square from lHS, we put under root in RHS
x=2/3 and -2/3
a=2/3 , b= -2/3
verification.,
on comparing with ax²+bx+c=0
a = 3
b=0
c=-2
sum of zeroes = a+b = -b/a( -coeff. of x)/(coeff. of x²)
=> 2/3-2/3=0/3
=> 0=0
product of zeroes = a.b = c/a ( constant term)/( coeff. of x²)
=> 2/3.-2/3 = -2/3
=> -4/6 = -2/3
=> -2/3 = -2/3
So , the roots are 2/3 & -2/3...
Hope , it helps you....
please hit like button and remark as brainliest answer.....
Anupreet12:
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Answered by
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hopeit will help you
In the general form of quadratic polynomial ax 2 + bx + c, there are two zeros say α and β, then; Sum of the zeros = α + β = -b/a = -(coefficient of x) / (coefficient of x 2)
please mark it as the brainlist answer
In the general form of quadratic polynomial ax 2 + bx + c, there are two zeros say α and β, then; Sum of the zeros = α + β = -b/a = -(coefficient of x) / (coefficient of x 2)
please mark it as the brainlist answer
please mark it as a brainlist answer
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