find the zeros of the quadratic polynomial 4x²-8x+3 and verify the relationship between the zeros and the coefficient
Answers
Step-by-step explanation:
Given,
a = 4 , b = -8 , c = 3
So,
Quadratic formula
= -b ±√b² - 4ac/2a
= -8 ± √8²- 4(4)(3) / 2(4)
= -8 ±√64 -48 / 8
= -8 ± √16 / 8
= -8 ± 4/8
So there are two possible outcome
1.-8 + 4/8
2. -8 - 4 /8
1.= -8+4/8 => 4/8=>1/2
2.= -8-4/8 => -12/8=> -3/2
So the zeros of polynomial are 1/2 and -3/2
Verification,
Sum of zeroes = 1/2+(-3/2)
= -2/2= -1
Product of zeroes = (1/2)*(-3/2)
=-3/2
Hope it helps(•‿•)