Question

find the zeros of the quadratic polynomial 4x²-8x+3 and verify the relationship between the zeros and the coefficient
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Answer 1

Step-by-step explanation:

Given,

a = 4 , b = -8 , c = 3

So,

Quadratic formula

= -b ±√b² - 4ac/2a

= -8 ± √8²- 4(4)(3) / 2(4)

= -8 ±√64 -48 / 8

= -8 ± √16 / 8

= -8 ± 4/8

So there are two possible outcome

1.-8 + 4/8

2. -8 - 4 /8

1.= -8+4/8 => 4/8=>1/2

2.= -8-4/8 => -12/8=> -3/2

So the zeros of polynomial are 1/2 and -3/2

Verification,

Sum of zeroes = 1/2+(-3/2)

= -2/2= -1

Product of zeroes = (1/2)*(-3/2)

=-3/2

Hope it helps(•‿•)