Find the zeros of the quadratic polynomial 6x2-3-7x and verify the relationship between the zeros and its coefficients
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Here is the answer.
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Here is the answer.
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Question :- 6x²-7x-3
=6x²+2x-9x-3
=2x(3x+1)-3(3x+1)
=(2x-3)(3x+1) = Zeroes !!
⇒2x-3=0
or
⇒3x+1=0
⇒x=3/2 ------(1)
or
⇒ x= - 1/3 ------(2)
Verification :-
α=3/2 ,β= - 1/3
✌α+β= -b/a
⇒3/2+(-1/3)= - (-3)/6
⇒3/2-1/3=1/2
⇒7/6 =1/2
✌ αβ=c/a
⇒ 3/2(-1/3)= -7/6
⇒-1/2= -7/6
⇒1/2=7/6
_______ Hope it helps you ______
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