Question

find the zeros of the quadratic polynomial 6x²+x-2 and verify the relationship between the zeros and coefficients​

Answer 1

Step-by-step explanation:

Let 6x^2+x-2=p(x)

p(x)=0

6x^2+x-2=0

6x^2-3x+4x-2=0

3x(2x-1)+2(2x-1)=0

(2x-1)(3x+2)=0

(2x-1)=0 or (3x+2)=0

2x=1 or 3x = -2

x= 1/2 or x = -2/3

LHS 6x^2+x-2 -------(1)

put x=1/2

6(1/2)^2+1/2-2

=6×1/4+1/2-2

=3/2+1/2-2=4/2-2

=0= p(x). =RHS(proved)

put x=-2/3 in equation (1)

6(-2/3)^2+(-2/3)-2

=6×4/9-2/3-2

=8/3-2/3-2=6/3-2

=0=p(x) =(RHS). (proved)

hope this will helpful.