Question

Find the zeros of the quadratic polynomial f(x) = 6x² - 3

Answer 1

f(x)=6x²-3

f(x)=0

6x²-3=0

6x²=3

x²=3/6

x²=1/2

x=±1/√2

x=1/√2 and x=-1/√2 are the zeroes of the polynomial f(x).

Answer 2

Answer:

$Zeroes \: of \\\: given \: polynomial \: are \:\\ x= -\frac{1}{\sqrt{2}}\: Or\: x = \frac{1}{\sqrt{2}}$

Explanation:

Given quadratic polynomial

f(x)=6x²-3

To find zeroes f(x), we must take

f(x)=0

$\implies 6x^{2}-3=0$

Divide each term by 3 , we get

$\implies 2x^{2}-1=0$

$\implies 2x^{2} = 1$

$\implies x^{2}= \frac{1}{2}$

$\implies x = ±\sqrt{\frac{1}{2}}$

$\implies x = ±\frac{1}{\sqrt{2}}$

$\implies x = -\frac{1}{\sqrt{2}}\: Or x = \frac{1}{\sqrt{2}}$

Therefore,

$Zeroes \: of \\\: given \: polynomial \: are \:\\ x = -\frac{1}{\sqrt{2}}\: Or\: x = \frac{1}{\sqrt{2}}$

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