Question

find the zeros of the quadratic polynomial f(x)= 6x2-3 and also verify the relationship between the zeros and its coefficients.

Answer 1

f(x) = 6x²-3
f(x) = 0
6x²-3 = 0
6x² = 3
x² = 3/6
x² = 1/2
x = 1/√2 , -1/√2
Roots of f(x) = 1/√2 , -1/√2
Verification = (i) 6(1/√2)² - 3
= 6(1/2) - 3
= 3-3
= 0
(ii) 6(-1/√2)² - 3
= 6(1/2) - 3
= 3-3
= 0

@skb

Answer 2

Answer:

Step-by-step explanation:

f(x) = 6x²-3

f(x) = 0

6x²-3 = 0

6x² = 3

x² = 3/6

x² = 1/2

x = 1/√2 , -1/√2

Roots of f(x) = 1/√2 , -1/√2

Verification = (i) 6(1/√2)² - 3

= 6(1/2) - 3

= 3-3

= 0

(ii) 6(-1/√2)² - 3

= 6(1/2) - 3

= 3-3

= 0

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