Question

find the zeros of the quadratic polynomial f x is equals to x square minus 3 x minus 28 and verify the relationship between the zeros and the coefficient of the polynomial​

Answer 1

Answer:

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Step-by-step explanation:

given that :

x²-3x-28 = x

=> x²-3x-x-28=0

=> x²-4x-28=0

now by middle term splitting method, we get :

=> x² -7x+4x-28=0

=> x(x-7) + 4(x-7)=0

=> (x+4)(x-7)=0

=> x= -4, 7

Verification :

sum of zeros =

$\alpha + \beta = \frac{ -b}{a}$

=> (-4)+7=